If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x^2=49=0
We move all terms to the left:
x^2-(49)=0
a = 1; b = 0; c = -49;
Δ = b2-4ac
Δ = 02-4·1·(-49)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14}{2*1}=\frac{-14}{2} =-7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14}{2*1}=\frac{14}{2} =7 $
| 1–8x+5=11–3x | | 8+2b=19 | | 3•(x-2)=12 | | 2x+1,5x-20=10+½x | | 3/5p+1=1/5p+8 | | 0.333+3)=-6y | | 0.5b+3.25=0.57 | | 13-9-x÷11=3x÷22+12.5 | | X—y=20 | | 6=4/9w+2/3 | | Y=0,75x-10 | | 8=t/109 | | 3(7x+4)=6(2x+3) | | Y/4+1=2y/4 | | 5y+2=y+18 | | 177147=3^x | | 6^x-5×6^x-2=186 | | D²-2d+5=0 | | 3^x2-5x+11=243 | | 3x2-5x+11=243 | | 3x2-5x+11=242 | | 7(2x+1)=48 | | 3x(4x–1)–4x(2x–3)–1=5+2x(2x+3) | | 2-188/x^2=0 | | 2-162/x^2=0 | | 5X+(7x10)=160 | | (2x+3x)*0,2=13 | | 21+x*3-x=131 | | 2^7x(8)=256x | | 2x+32-22=x+40 | | -4(3x+1)=8 | | 6p+14=2 |